如果要选择 time 为2014-12-18那天的数据：采用正则化来处理
import re regex = re.compile(r‘^2014-12-18+ /d+$‘) def datefun(data): if re.match(regex,data[‘time‘]): date,time = data[‘time‘].split(‘ ‘) return date else: return None data[‘time‘] = data.apply(datefun,axis = 1) data = data[(data[‘time‘] == ‘2014-12-18‘)]
原文：https://www.cnblogs.com/Lee-yl/p/9696058.html