Time Limit: 6000/6000 MS (Java/Others) Memory Limit: 510000/510000 K (Java/Others)
Total Submission(s): 5248 Accepted Submission(s): 2014
#include <bits/stdc++.h> using namespace std; typedef long long LL; const int maxn = 45; const int maxm = (1<<20); int a[maxn]; LL dp[2][maxm]; int main() { int t; scanf("%d", &t); for(int k = 1; k <= t; k++) { int n, m; scanf("%d%d", &n, &m); for(int i = 1; i <= n; i++) { scanf("%d", &a[i]); } memset(dp, 0, sizeof(dp)); dp[0][0] = 1; int pre = 0, now = 1; for(int i = 1; i <= n; i++) { for(int j = 0; j < maxm; j++) { int x = a[i] ^ j; dp[now][x] = dp[pre][x] + dp[pre][j]; } swap(now, pre); } LL ans = 0; for(int i = m; i < maxm; i++) { ans += dp[pre][i]; } printf("Case #%d: %lld\n", k, ans); } return 0; }
原文:https://www.cnblogs.com/songorz/p/9710614.html