1.用列表+循环实现，并包装成函数
def pySum(n): a = list(range(10)) b = list(range(0, 60, 6)) c = [] for i in range(len(a)): c.append(a[i] ** 2 + b[i] ** 3) return(c) print(pySum(10))
2.用numpy实现，并包装成函数
import numpy def npSum(n): a = numpy.arange(10) b = numpy.arange(0, 60, 6) c = a + b return(c) print(npSum(10))
3.对比两种方法实现的效率，给定一个较大的参数n，用运行函数前后的timedelta表示。
def pySum(n): a=list(range(n)) b=list(range(0,5*n,5)) c=[] for i in range(len(a)): c.append(a[i]**2+b[i]**3) return(c) print(pySum(10)) def npSum(n): a=list(range(n)) b=list(range(0,5*n,5)) c=[] for i in range(len(a)): c.append(a[i]**2+b[i]**3) return(c) print(pySum(10)) from datetime import datetime start = datetime.now() pySum(2000000) delta=datetime.now()-start print(delta) start= datetime.now() npSum(2000000) delta=datetime.now()-start print(delta)
原文：https://www.cnblogs.com/a-zhuanger/p/9722941.html