首页 > 其他 > 详细

leetcode_38

时间:2018-10-02 10:19:02      阅读:143      评论:0      收藏:0      [点我收藏+]

---恢复内容开始---

The count-and-say sequence is the sequence of integers with the first five terms as following:

1.     1
2.     11
3.     21
4.     1211
5.     111221

1 is read off as "one 1" or 11.
11 is read off as "two 1s" or 21.
21 is read off as "one 2, then one 1" or 1211.

Given an integer n where 1 ≤ n ≤ 30, generate the nth term of the count-and-say sequence.

Note: Each term of the sequence of integers will be represented as a string.

 

Example 1:

Input: 1
Output: "1"

Example 2:

Input: 4
Output: "1211"

SOLUTION1:
利用itertools中的groupby函数,还原过程:
import itertools


class Solution(object):
    def countAndSay(self, n):
        """
        :type n: int
        :rtype: str
        """
        s = 1
        for _ in range(n - 1):
            s = ‘‘.join(str(len(list(group))) + digit
                        for digit, group in itertools.groupby(s))
        return s

 

 

 

---恢复内容结束---

leetcode_38

原文:https://www.cnblogs.com/francischeng/p/9736302.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!