2018.09.29 作业五

#a1,a2,a3 ,·····,an
#b1,b2,b3 ,·····,bn
#求：
#a1+b1,a2+b2,a3 +b3,·····+an+bn

#1、列表+循环 实现，并包装成一个函数

def pySum(n):
    a = list(range(10))
    b = list(range(0, 50, 5))
    c = []
    for i in range(len(a)):
        c.append(a[i] ** 2 + b[i] ** 3)
    return(c)

print(pySum(10))

import numpy
def npSum(n):
    a = numpy.arange(10)
    b = numpy.arange(0, 50, 5)
    c = a + b
    return(c)

print(npSum(10))

from datetime import  datetime
start = datetime.now()
pySum(100000)
delta = datetime.now()-start
print(delta)

start= datetime.now()
npSum(100000)
delta = datetime.now()-start
print(delta)