Sort a linked list using insertion sort.
题目要求:链表的插入排序,由于没有时间复杂度的要求,可以直接循环操作。
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* insert(ListNode* head,int num){ ListNode *node = new ListNode(num); if(head==NULL || num <= head->val){ node->next=head; return node; } ListNode *pre = head; ListNode *tail = head->next; while(tail!=NULL && num > tail->val){ // 一定要注意tail!=NULL 先决条件 pre= tail; tail=tail->next; } node->next = pre->next; pre->next = node; return head; } ListNode* insertionSortList(ListNode *head){ if(head==NULL || head->next==NULL) return head; ListNode *tmp = head; ListNode* ans=NULL; while(tmp!=NULL){ ans = insert(ans,tmp->val); tmp =tmp->next; } return ans; } };
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[LeetCode 题解]: Insertion Sort List,布布扣,bubuko.com
[LeetCode 题解]: Insertion Sort List
原文:http://www.cnblogs.com/double-win/p/3873881.html