首页 > 其他 > 详细

LeetCode 35. Search Insert Position

时间:2018-10-15 21:07:00      阅读:164      评论:0      收藏:0      [点我收藏+]

分析

难度 易

来源

https://leetcode.com/problems/search-insert-position/description/

题目

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You may assume no duplicates in the array.

Example 1:

Input: [1,3,5,6], 5
Output: 2

Example 2:

Input: [1,3,5,6], 2
Output: 1

Example 3:

Input: [1,3,5,6], 7
Output: 4

Example 4:

Input: [1,3,5,6], 0
Output: 0

解答

 1 package LeetCode;
 2 
 3 public class L35_SearchInsertPosition {
 4     public int searchInsert(int[] nums, int target) {
 5         int pos=0;
 6         int len=nums.length;
 7         if(len==0)
 8             return pos;
 9         else if(len==1){
10             if(nums[0]>=target)
11                 pos=0;
12             else
13                 pos=1;
14         }else{
15             for(int i=0;i<len;i++)
16             {
17                 if(nums[i]<target)
18                     pos++;
19                 else
20                     break;
21             }
22         }
23         return pos;
24     }
25 }

LeetCode 35. Search Insert Position

原文:https://www.cnblogs.com/flowingfog/p/9794691.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!