LeetCode : reverse integer

 1 class Solution {
 2 public:
 3     int reverse(int x) {
 4         int signal = (x>0)? 1:-1;   /* signal记录正负号 */
 5         x=abs(x);
 6         int tmp = 0;
 7 
 8         if(x == 0)
 9             return x;
10 
11         while(x)
12         {
13             tmp = tmp*10+x%10;
14             x = x/10;
15         }
16 
17         tmp = tmp*signal;      /* 乘上符号 */
18 
19         return tmp;
20     }
21 };