P1067 多项式输出

#include <iostream>
#include<cstdio>
#include<algorithm>
using namespace std;
int a[109];
int main()
{
    int n,i;
    scanf("%d",&n);
    for(i=n;i>=0;i--) scanf("%d",&a[i]);
    for(i=n;i>1;i--)
    {
        if(a[i]==0) continue;
        if(i==n) {
                if(a[i]!=1&&a[i]!=-1){
                    printf("%dx^%d",a[i],i);
                    continue;
                }
                else if(a[i]==1){
                    printf("x^%d",i);
                    continue;
                }
                else if(a[i]==-1){
                    printf("-x^%d",i);
                    continue;
                }
        }
        else if(a[i]>0) printf("+");
        if(a[i]==1)
        {
            printf("x^%d",i);
            continue;
        }
        else if(a[i]==-1)
        {
            printf("-x^%d",i);
            continue;
        }
        else printf("%dx^%d",a[i],i);
    }
    if(a[1]==1) printf("+x");
    else if(a[1]>0&&a[1]!=1) printf("+%dx",a[1]);
    else if(a[1]==-1) printf("-x");
    else if(a[1]<0&&a[1]!=-1) printf("%dx",a[1]);
    if(a[0]>0) printf("+%d",a[0]);
    else if(a[0]<0) printf("%d",a[0]);
    return 0;
}

P1067 多项式输出

原文：https://www.cnblogs.com/EchoZQN/p/9995871.html