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LeetCode 383. Ransom Note

时间:2018-12-03 22:31:14      阅读:146      评论:0      收藏:0      [点我收藏+]

Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return false.

Each letter in the magazine string can only be used once in your ransom note.

Note:

You may assume that both strings contain only lowercase letters.

canConstruct("a", "b") -> false
canConstruct("aa", "ab") -> false
canConstruct("aa", "aab") -> true
class Solution {
public:
    bool canConstruct(string ransomNote, string magazine) {
         map<char, int> visited;
         for(int i=0; i<magazine.size(); i++)
             visited[magazine[i]]++;
         for(int i=0; i<ransomNote.size(); i++){
             visited[ransomNote[i]]--;
             if(visited[ransomNote[i]]<0)
                 return false;
         }
        return true;
    }
};

LeetCode 383. Ransom Note

原文:https://www.cnblogs.com/A-Little-Nut/p/10061294.html

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