对列表里的字典按年龄从小到大排序
infors=[{‘name‘:‘laowang‘,‘age‘:10},{‘name‘:‘xiaoming‘,‘age‘:30},{‘name‘:‘hehe‘,‘age‘:20}] infors.sort(key=lambda x:x[‘age‘]) print(infors)
原文：https://www.cnblogs.com/z-x-y/p/10090746.html
