Triangle leetcode java

题目：

Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row below.

For example, given the following triangle

[
     [2],
    [3,4],
   [6,5,7],
  [4,1,8,3]
]

The minimum path sum from top to bottom is 11 (i.e., 2 + 3 + 5 + 1 = 11).

Note:
Bonus point if you are able to do this using only O(n) extra space, where n is the total number of rows in the triangle.

题解：

一道动态规划的经典题目。需要自底向上求解。

递推公式是： dp[i][j] = dp[i+1][j] + dp[i+1][j+1] ，当前这个点的最小值，由他下面那一行临近的2个点的最小值与当前点的值相加得到。

由于是三角形，且历史数据只在计算最小值时应用一次，所以无需建立二维数组，每次更新1维数组值，最后那个值里存的就是最终结果。

代码如下：

Reference:  http://www.programcreek.com/2013/01/leetcode-triangle-java/

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Triangle leetcode java

原文：http://www.cnblogs.com/springfor/p/3887908.html