Follow up for problem "Populating Next Right Pointers in Each Node".
What if the given tree could be any binary tree? Would your previous solution still work?
Note:
For example, Given the following binary tree,
1 / 2 3 / \ 4 5 7
After calling your function, the tree should look like:
1 -> NULL / 2 -> 3 -> NULL / \ 4-> 5 -> 7 -> NULL
class Solution { public: void connect(TreeLinkNode *root) { if(root==NULL) return; root->next = NULL; fun(root); } private: TreeLinkNode *FindPleft(TreeLinkNode *&parent){ TreeLinkNode *pleft =NULL; while(parent!=NULL){ if(parent->left!=NULL){ pleft = parent->left; break; }else if(parent->left==NULL && parent->right!=NULL){ pleft = parent->right; break; }else{ parent = parent->next; continue; } }//end while return pleft; } void fun(TreeLinkNode *parent){ if(parent==NULL) return ; TreeLinkNode *pleft = FindPleft(parent); TreeLinkNode *pl; TreeLinkNode *nextLevelParent = pleft; while(parent!=NULL){ if(pleft==parent->left &&parent->right!=NULL){ pleft->next = parent->right; pleft = pleft->next; }else if((pleft!=NULL && pleft==parent->left && parent->right==NULL)||pleft==parent->right){ parent = parent->next; if(parent==NULL||FindPleft(parent)==NULL){ pleft->next = NULL; parent = nextLevelParent; pl = FindPleft(parent); pleft = pl; nextLevelParent = pleft; }else{ pl = FindPleft(parent); pleft->next = pl; pleft = pl; } }//end if }//end while } };
[LeetCode] Populating Next Right Pointers in Each Node II,布布扣,bubuko.com
[LeetCode] Populating Next Right Pointers in Each Node II
原文:http://www.cnblogs.com/Xylophone/p/3889542.html