# 字符串替换 s = " work hard" print(s.replace(‘r‘, ‘0‘)) # new replace old print(s.replace(‘wo‘, ‘01‘)) print(s.replace(‘d‘, ‘0‘)) # old not in s， return s print(s.replace(‘r‘, ‘0‘, 1)) # count=1
原文：https://www.cnblogs.com/ShuComputerProgram/p/10337299.html