Implement wildcard pattern matching with support for ‘?‘
and ‘*‘
.
‘?‘ Matches any single character. ‘*‘ Matches any sequence of characters (including the empty sequence). The matching should cover the entire input string (not partial). The function prototype should be: bool isMatch(const char *s, const char *p) Some examples: isMatch("aa","a") → false isMatch("aa","aa") → true isMatch("aaa","aa") → false isMatch("aa", "*") → true isMatch("aa", "a*") → true isMatch("ab", "?*") → trueisMatch("aab", "c*a*b") → false
class Solution { public: bool isMatch(const char *s, const char *p) { const char * ptr; const char *str; bool start = false; for(ptr=p,str=s; *str!='\0' ; ){ switch(*ptr){ case '?': str++,ptr++; break; case '*': start = true; while(*ptr == '*') ptr++; if(*ptr=='\0') return true; p = ptr; s = str; break; default: if(*ptr != *str){ if(!start) return false; ptr = p; str = s+1; s=s+1; } else{ ptr++; str++; } } } while(*ptr=='*') ptr++; return (*ptr == '\0'); } };
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原文:http://blog.csdn.net/qq112928/article/details/38377245