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leetcode 42. Trapping Rain Water

时间:2019-02-01 23:23:21      阅读:221      评论:0      收藏:0      [点我收藏+]

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining.

技术分享图片
The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of rain water (blue section) are being trapped. Thanks Marcos for contributing this image!

Example:

Input: [0,1,0,2,1,0,1,3,2,1,2,1]
Output: 6

class Solution {
  public int trap(int[] A){
    int a=0;
    int b=A.length-1;
    int max=0;
    int leftmax=0;
    int rightmax=0;
    while(a<=b){
        leftmax=Math.max(leftmax,A[a]);
        rightmax=Math.max(rightmax,A[b]);
        if(leftmax<rightmax){
            max+=(leftmax-A[a]);       // leftmax is smaller than rightmax, so the (leftmax-A[a]) water can be stored
            a++;
        }
        else{
            max+=(rightmax-A[b]);
            b--;
        }
    }
    return max;
  }
}

 

leetcode 42. Trapping Rain Water

原文:https://www.cnblogs.com/jamieliu/p/10347244.html

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