int qmi(int a, int b, int p)
{
int res = 1;
while (b)
{
if (b&1) res = (res * a) % p;
a = (a * a) % p;
b = b>> 1;
}
return res;
}
int qji(int a, int b, int p)
{
int res = 0;
while (b)
{
if (b&1) res = (res + a) % p;
a = (a * 2) % p;
b = b>> 1;
}
return res;
}
#include<bits/stdc++.h>
using namespace std;
long long a,b,p;
int main()
{
ios::sync_with_stdio(0);
cin>>a>>b>>p;
long long res=0;
while(b)
{
if(b&1)res=(res+a)%p;//必须先加起来再取余 括号不能去
a=a*2%p;
b=b>>1;
}
cout<<res%p<<"\n";
return 0;
}
原文:https://www.cnblogs.com/52dxer/p/10353029.html