list1 = [[‘张三‘,‘男‘,‘未婚‘,20],[‘李四‘,‘男‘,‘已婚‘,28],[‘小红‘,‘女‘,‘未婚‘,18],[‘小芳‘,‘女‘,‘已婚‘,25]] output = open(‘data.xls‘,‘w‘,encoding=‘gbk‘) output.write(‘name\tgender\tstatus\tage\n‘) for i in range(len(list1)): for j in range(len(list1[i])): output.write(str(list1[i][j])) #write函数不能写int类型的参数，所以使用str()转化 output.write(‘\t‘) #相当于Tab一下，换一个单元格 output.write(‘\n‘) #写完一行立马换行 output.close()
list1 = [[‘张三‘,‘男‘,‘未婚‘,20],[‘李四‘,‘男‘,‘已婚‘,28],[‘小红‘,‘女‘,‘未婚‘,18],[‘小芳‘,‘女‘,‘已婚‘,25]] output = open(‘data.txt‘,‘w‘,encoding=‘gbk‘) output.write(‘name,gender,status,age\n‘) for row in list1: rowtxt = ‘{},{},{},{}‘.format(row[0],row[1],row[2],row[3]) output.write(rowtxt) output.write(‘\n‘) output.close()
组合
combinations：不考虑顺序的排列组合 import itertools print list(itertools.combinations([1,2,3,4],3)) [(1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)] permutations：考虑顺序的排列组合 import itertools print list(itertools.permutations([1,2,3,4],2)) #第二个参数2表示要选几个对象 [(1, 2), (1, 3), (1, 4), (2, 1), (2, 3), (2, 4), (3, 1), (3, 2), (3, 4), (4, 1), (4, 2), (4, 3)]
from itertools import product l = [1, 2, 3] print (list(product(l, l))) print (list(product(l, repeat=3))) 结果： [(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (2, 3), (3, 1), (3, 2), (3, 3)] [(1, 1, 1), (1, 1, 2), (1, 1, 3), (1, 2, 1), (1, 2, 2), (1, 2, 3), (1, 3, 1), (1, 3, 2), (1, 3, 3), (2, 1, 1), (2, 1, 2), (2, 1, 3), (2, 2, 1), (2, 2, 2), (2, 2, 3), (2, 3, 1), (2, 3, 2), (2, 3, 3), (3, 1, 1), (3, 1, 2),
(3, 1, 3), (3, 2, 1), (3, 2, 2), (3, 2, 3), (3, 3, 1), (3, 3, 2), (3, 3, 3)]
from functools import reduce fn = lambda x, code=‘,‘: reduce(lambda x, y: [str(i)+code+str(j) for i in x for j in y], x) # 直接调用fn(lists, code) list1 = [1, 2] list2 = [3, 4] list3 = [5, 6] res = fn([list1, list2, list3]) print(res) [‘1,3,5‘, ‘1,3,6‘, ‘1,4,5‘, ‘1,4,6‘, ‘2,3,5‘, ‘2,3,6‘, ‘2,4,5‘, ‘2,4,6‘]
一、笛卡尔积：itertools.product(*iterables[, repeat]) 直接对自身进行笛卡尔积： import itertools for i in itertools.product(‘ABCD‘, repeat = 2): print (‘‘.join(i),end=‘ ‘) 输出结果： AA AB AC AD BA BB BC BD CA CB CC CD DA DB DC DD print (”.join(i))这个语句可以让结果直接排列到一起 end=’ ‘可以让默认的输出后换行变为一个空格 两个元组进行笛卡尔积： import itertools a = (1, 2, 3) b = (‘A‘, ‘B‘, ‘C‘) c = itertools.product(a,b) for i in c: print(i,end=‘ ‘) 输出结果： (1, ‘A’) (1, ‘B’) (1, ‘C’) (2, ‘A’) (2, ‘B’) (2, ‘C’) (3, ‘A’) (3, ‘B’) (3, ‘C’) 二、排列：itertools.permutations(iterable[, r]) import itertools for i in itertools.permutations(‘ABCD‘, 2): print (‘‘.join(i),end=‘ ‘) 输出结果： AB AC AD BA BC BD CA CB CD DA DB DC 三、组合：itertools.combinations(iterable, r) import itertools for i in itertools.combinations(‘ABCD‘, 3): print (‘‘.join(i)) 输出结果： ABC ABD ACD BCD 四、组合（包含自身重复）：itertools.combinations_with_replacement(iterable, r) import itertools for i in itertools.combinations_with_replacement(‘ABCD‘, 3): print (‘‘.join(i),end=‘ ‘) 输出结果： AAA AAB AAC AAD ABB ABC ABD ACC ACD ADD BBB BBC BBD BCC BCD BDD CCC CCD CDD DDD
原文：https://www.cnblogs.com/xaiobong/p/10368039.html
