1.使用while循环输出1.2.3.4.5.6.8.9.10
2.求1-100的所有数之和
3.输出1-100的内所有奇数
4.输出1-100内的所有偶数
5.求1-2+3-4+5.。。。99之和
6.用户登录(3次机会)
解答:
1.
#/usr/bin python #-*-coding:utf8-*- count = 1 while count <=10: if count!=7: print(count) count=count+1
2.
#/usr/bin python #-*-coding:utf8-*- count=1 n=1 while count<100: count=count+1 n=n+count print(n)
3.
#/usr/bin python #-*-coding:utf8-*- count=1 n=1 while count<99: count=count+2 n=n+count print(n)
4.
#/usr/bin python #-*-coding:utf8-*- count=2 n=2 while count<100: count=count+2 n=n+count print(n)
5.
#/usr/bin python #-*-coding:utf8-*- count=1 n=1 while count<99: count=count+1 if count%2 == 0: n=n-count else: n=n+count print(n)
6
#/usr/bin python #-*-coding:utf8-*- count=3 while count!=0: count=count-1 inp1=input("请输入用户:") inp2=input("请输入密码:") if inp1=="zengtao": if inp2=="zt": print("正确,欢迎",inp1) count=0 else: print("密码错误,请重试") print("您还有",count,"次机会") else: print("用户或密码错误,请重试") print("您还有",count,"次机会")
原文:https://www.cnblogs.com/zengtaoyunwei/p/10371631.html