Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A and B, as 167334 / (167 × 334) = 3. Given an integer Z, you are supposed to test if it is such an integer.
Each input file contains one test case. For each case, the first line gives a positive integer N (≤ 20). Then N lines follow, each gives an integer Z (10 ≤ Z <2?31??). It is guaranteed that the number of digits of Z is an even number.
For each case, print a single line Yes if it is such a number, or No if not.
3
167334
2333
12345678
Yes
No
No
1 #include <stdio.h> 2 #include <string> 3 #include <iostream> 4 using namespace std; 5 int s2n(string s){ 6 int res=0; 7 for(int i=0;i<s.length();i++){ 8 res = 10*res + s[i]-‘0‘; 9 } 10 return res; 11 } 12 int main(){ 13 string s; 14 int n; 15 scanf("%d",&n); 16 for(int i=0;i<n;i++){ 17 cin>>s; 18 int pos=s.length()/2; 19 string s1,s2; 20 int n1,n2; 21 s1=s.substr(0,pos); 22 s2=s.substr(pos,s.length()-pos); 23 n1=s2n(s1); 24 n2=s2n(s2); 25 if((n1==0 || n2==0) || s2n(s)%(n1*n2)!=0)printf("No\n"); 26 else printf("Yes\n"); 27 } 28 }
注意点：后面两个测试点是其中一半为0的情况，要额外判断。显示浮点错误说明除数遇到了0。
原文：https://www.cnblogs.com/tccbj/p/10423443.html
