//循环实现
void merge(int arr[], int l, int m, int r) { int i, j, k; int n1 = m - l + 1; int n2 = r - m; int L[n1], R[n2]; for (i = 0; i < n1; i++) L[i] = arr[l + i]; for (j = 0; j < n2; j++) R[j] = arr[m + 1+ j]; i = 0; j = 0; k = l; while (i < n1 && j < n2) { if (L[i] <= R[j]) { arr[k] = L[i]; i++; } else{ arr[k] = R[j]; j++; } k++; } while (i < n1) { arr[k] = L[i]; i++; k++; } while (j < n2) { arr[k] = R[j]; j++; k++; } } void merge_sort(int arr[], int l, int r) { if (l < r) { int m = l+(r-l)/2; mergeSort(arr, l, m); mergeSort(arr, m+1, r); merge(arr, l, m, r); } }
//递归实现 void merge(int arr[], int tmp[], int start, int end, int middle) { int l, r, s; s = start; l = start; r = middle + 1; while (l <= middle && r <= end) { if (arr[l] <= arr[r]) tmp[s++] = arr[l++]; else tmp[s++] = arr[r++]; } while (l <= middle) tmp[s++] = arr[l++]; while (r <= end) tmp[s++] = arr[r++]; for (;start <= end;start++) arr[start] = tmp[start]; } void msort(int arr[], int *tmp, int start, int end) { int middle; if (start < end) { middle = (start + end) / 2; msort(arr, tmp, start, middle); msort(arr, tmp, middle + 1, end); merge(arr, tmp, start, end, middle); } } void merge_sort(int arr[], int n) { int *tmp = (int*)malloc(n*sizeof(int)); msort(a, tmp, 0, n - 1); free(tmp); }
空间效率:O(n)
时间效率:最好情况:O(Nlog2N) 平均情况:O(Nlog2N) 最坏情况:O(Nlog2N)
稳定性(相同元素相对位置变化情况):稳定
原文:https://www.cnblogs.com/wanghao-boke/p/10424405.html