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#include<stdio.h> #include<string.h> #define N 100005 __int64 cnt, k; int a[N],c[N]; //归并排序的合并操作 void merge(int a[], int first, int mid, int last, int c[]) { int i = first, j = mid + 1; int m = mid, n = last; int k = 0; while(i <= m || j <= n) { if(j > n || (i <= m && a[i] <= a[j])) c[k++] = a[i++]; else { c[k++] = a[j++]; cnt += (m - i + 1); } } for(i = 0; i < k; i++) a[first + i] = c[i]; } //归并排序的递归分解和合并 void merge_sort(int a[], int first, int last, int c[]) { if(first < last) { int mid = (first + last) / 2; merge_sort(a, first, mid, c); merge_sort(a, mid+1, last, c); merge(a, first, mid, last, c); } } int main() { int n; while(~scanf("%d%I64d",&n,&k)) { memset(c, 0, sizeof(c)); cnt = 0; for(int i = 0; i < n; i++) scanf("%d", &a[i]); merge_sort(a, 0, n-1, c); if(k >= cnt) cnt = 0; else cnt -= k; printf("%I64d\n",cnt); } }
hdu 4911 Inversion(归并排序求逆序对数),布布扣,bubuko.com
原文:http://blog.csdn.net/lyhvoyage/article/details/38395439