题目大意
分析
代码
#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
#include<algorithm>
#include<cctype>
#include<cmath>
#include<cstdlib>
#include<queue>
#include<ctime>
#include<vector>
#include<set>
#include<map>
#include<stack>
using namespace std;
#define int long long
int vis[1000100],a[1000100],b[1000100],p1[1000100],p2[1000100];
signed main(){
int n,m,i,j,k=0,l1,l2,r1,r2;
scanf("%lld",&n);
for(i=1;i<=n;i++)scanf("%lld",&a[i]),a[i]+=a[i-1];
for(i=1;i<=n;i++)scanf("%lld",&b[i]),b[i]+=b[i-1];
if(a[n]>b[n]){
k=1;
for(i=1;i<=n;i++)swap(a[i],b[i]);
}
int L=0;
for(i=0;i<=n;i++){
while(L<n&&b[L+1]<=a[i])L++;
int sum=a[i]-b[L];
if(vis[sum]){
l1=p1[sum]+1,l2=p2[sum]+1;
r1=i,r2=L;
break;
}else {
vis[sum]=1;
p1[sum]=i,p2[sum]=L;
}
}
if(k)swap(l1,l2),swap(r1,r2);
printf("%lld\n",r1-l1+1);
for(i=l1;i<=r1;i++)printf("%lld ",i);
puts("");
printf("%lld\n",r2-l2+1);
for(i=l2;i<=r2;i++)printf("%lld ",i);
return 0;
}
原文:https://www.cnblogs.com/yzxverygood/p/10463210.html