python中实现字符串使用非"+"号拼接的方式实现

例句sql是链接到hive库进行的查询操作
代码如下

imsis = (‘460020291****15‘, ‘46002029****6391‘)
    # 构造新数列
    # i = "("
    # for s in imsis:
    #     i = i + s + ","
    # i = i.strip(‘,‘) + ")"
    items = (‘460020291****15‘, ‘46002029****6391‘)
    items_tmp = ",".join(items)
    items_str = "%s%s%s" %("(", items_tmp, ")")
    if imsis:
        sql = "select bill_id, imsi as IMSI from data_tmp.bill_imsi where imsi in %s limit 10" %items_str
    else:
        sql = "select bill_id, imsi as IMSI from data_tmp.bill_imsi limit 10"
    print(sql)
    con2hive(sql=sql)

注释：
items_tmp = ",".join(items) 实现对元组items根据,以逗号“,”进行分割组成新字符con2hive(sql=sql) 调用链接hive数据仓库的执行函数
输入内容如下

注:列表或元组中必须为字符串才能使用join进行拼接

python中实现字符串使用非"+"号拼接的方式实现

原文：https://blog.51cto.com/maoxiaoxiong/2357425