Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.
If the last word does not exist, return 0.
class Solution(object): def lengthOfLastWord(self, s): """ :type s: str :rtype: int """ s=s.split() if(len(s)==0): return 0 s=len(s[-1]) return s
leetcode 58-> Length of Last Word
原文：https://www.cnblogs.com/sea-stream/p/10532820.html