复杂的sql语句,按部门统计人数:
--按部门统计人数 SELECT o.OUGUID AS OUGUID, o.OUNAME AS OUNAME, IFNULL(COUNT(DISTINCT o.USERGUID), 0) AS USERNUM, SUM(CASE WHEN IFNULL(q.CALLTIME, 0) != 0 THEN 1 ELSE 0 END) AS CallNoCount, SUM(CASE WHEN q.ROW_ID = ‘1‘ THEN 1 ELSE 0 END) AS QuestionCount, SUM(CASE WHEN q.`STATUS` = ‘3‘ THEN 1 ELSE 0 END) AS PassCount, SUM(CASE WHEN q.`STATUS` = ‘1‘ OR q.`STATUS` = ‘2‘ THEN 1 ELSE 0 END) AS BanjianCount FROM (SELECT ROW_ID,`STATUS`,handleuserguid,CALLTIME FROM audit_queue UNION ALL SELECT ROW_ID,`STATUS`,handleuserguid,CALLTIME FROM audit_queue_history) q LEFT JOIN (SELECT o.OUNAME,o.OUGUID,u.USERGUID, u.DISPLAYNAME FROM frame_user u LEFT JOIN frame_ou o ON u.OUGUID = o.OUGUID) o ON q.handleuserguid = o.USERGUID WHERE q.CALLTIME BETWEEN ‘2018-09-30 00:00:00‘ AND ‘2018-10-30 23:59:59‘ GROUP BY o.OUGUID;
其中类似 SUM(CASE WHEN q.ROW_ID = ‘1‘ THEN 1 ELSE 0 END) AS QuestionCount 为按一定的条件计数;
原文:https://www.cnblogs.com/wmqiang/p/10544042.html