递归与二叉树_leetcode450

# Definition for a binary tree node.
# class TreeNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Solution1(object):
    def deleteNode(self, root, key):
        """
        :type root: TreeNode
        :type key: int
        :rtype: TreeNode
        """
        if not root:
            return root

        if root.val > key:
            root.left = self.deleteNode(root.left,key)
            return root
        elif root.val < key :
            root.right = self.deleteNode(root.right,key)
            return root

        else:
            if not root.left:
                successor = root.right
                root.right = None
                return successor
            if not root.right:
                successor = root.left
                root.left = None
                return successor

            successor = self.minNode(root.right)

            successor.right = self.removeMin(root.right)
            successor.left = root.left

            root.left = None
            root.right = None

            return successor


    def minNode(self,root):
        if not root.left:
            return root
        return self.minNode(root.left)

    def maxNode(self,root):
        if not root.right:
            return root
        return self.maxNode(root.right)

    def removeMin(self,root):

        if not root.left:
            successor = root.right
            root.right = None
            return successor
        root.left = self.removeMin(root.left)
        return root




    def removeMax(self,root):
        if not root.right :
            successor = root.left
            root.left = None
            return successor
        root.right = self.removeMax(root.right)
        return  root


class Solution2(object):
    def deleteNode(self, root, key):
        """
        :type root: TreeNode
        :type key: int
        :rtype: TreeNode
        """
        if not root:
            return root

        if root.val > key:
            root.left = self.deleteNode(root.left,key)
            return root
        elif root.val < key :
            root.right = self.deleteNode(root.right,key)
            return root

        else:
            if not root.left:
                successor = root.right
                root.right = None
                return successor
            if not root.right:
                successor = root.left
                root.left = None
                return successor

            successor = self.maxNode(root.left)

            successor.left = self.removeMax(root.left)
            successor.right = root.right

            root.left = None
            root.right = None

            return successor


    def minNode(self,root):
        if not root.left:
            return root
        return self.minNode(root.left)

    def maxNode(self,root):
        if not root.right:
            return root
        return self.maxNode(root.right)

    def removeMin(self,root):

        if not root.left:
            successor = root.right
            root.right = None
            return successor
        root.left = self.removeMin(root.left)
        return root





    def removeMax(self,root):
        if not root.right :
            successor = root.left
            root.left = None
            return successor
        root.right = self.removeMax(root.right)
        return root

递归与二叉树_leetcode450

原文：https://www.cnblogs.com/lux-ace/p/10546821.html