查找表_leetcode217

# 解题思路：字典存储计数状态  20190302 找工作期间

class Solution(object):
    def containsDuplicate(self, nums):
        """
        :type nums: List[int]
        :rtype: bool
        """

        record =  {}

        for i in range(len(nums)):
            record[nums[i]]=record.get(nums[i],0)+1
            if record[nums[i]] >= 2:
                return True


        return False

查找表_leetcode217

原文：https://www.cnblogs.com/lux-ace/p/10546919.html