import os from flask import Flask, request from werkzeug import secure_filename # 获取上传文件的文件名 UPLOAD_FOLDER = r‘D:\file‘ # 上传路径 ALLOWED_EXTENSIONS = set([‘txt‘, ‘pdf‘, ‘png‘, ‘jpg‘, ‘jpeg‘, ‘gif‘,‘doc‘]) # 允许上传的文件类型 app = Flask(__name__) app.config[‘UPLOAD_FOLDER‘] = UPLOAD_FOLDER def allowed_file(filename): # 验证上传的文件名是否符合要求，文件名必须带点并且符合允许上传的文件类型要求，两者都满足则返回 true return ‘.‘ in filename and filename.rsplit(‘.‘, 1)[1] in ALLOWED_EXTENSIONS @app.route(‘/‘, methods=[‘GET‘, ‘POST‘]) def upload_file(): if request.method == ‘POST‘: # 如果是 POST 请求方式 file = request.files[‘file‘] # 获取上传的文件 if file and allowed_file(file.filename): # 如果文件存在并且符合要求则为 true filename = secure_filename(file.filename) # 获取上传文件的文件名 file.save(os.path.join(app.config[‘UPLOAD_FOLDER‘], filename)) # 保存文件 return ‘{} upload successed!‘.format(filename) # 返回保存成功的信息 # 使用 GET 方式请求页面时或是上传文件失败时返回上传文件的表单页面 return ‘‘‘ <!doctype html> <title>Upload new File</title> <h1>Upload new File</h1> <form action="" method=post enctype=multipart/form-data> <p><input type=file name=file> <input type=submit value=Upload> </form> ‘‘‘ if __name__ == ‘__main__‘: app.run()
原文：https://www.cnblogs.com/wl443587/p/10552542.html