name = "dongfei"
if "d" in name: #not in
print('OK')
else:
print("ERROR")
user = 'dongfei'
passwd = '123456'
gender = 'M'
result = gender == "M" and (user == "dongfei" and passwd == "123456") #先计算括号内的
print(result)
a = "123"
b = int(a) #将字符串转换为整型
print(type(b)) #查看对象的数据类型
a = "0011"
b = int(a, base=2) #将a以2进制的方式转换为十进制
print(type(b))
print(b)
age = 10
r = age.bit_length()
print(r)
- 字符串不允许修改
s4 = "admininad"
print(s4.find("in"))
s2 = "Dongfei"
print(s2.casefold())
print(s2.lower())
print(s2.islower())
print(s2.upper())
print(s2.isupper())
print(s2.swapcase())
s2 = "Dongfei"
print(s2.center(20,"#")) #######Dongfei#######
print(s2.ljust(20,"#")) #Dongfei#############
print(s2.rjust(20,"#")) ##############Dongfei
print(s2.zfill(20)) #0000000000000Dongfei
s3 = "dongfeiii"
print(s3.count('i',5,7))
print(s3.endswith('i'))
print(s3.startswith('d'))
s4 = "admininad"
print(s4.find("in"),7,8)
print(s4.index("in"))
s5 = 'i am {name}'
print(s5.format(name="dongfei"))
print(s5.format( **{"name":"dongfei"} ))
print(s5.format_map( {"name":"dongfei"} ))
s6 = 'i am {0}, age {1}'
print(s6.format("dongfei",18))
s7 = "asdf9234"
print(s7.isalnum()) #是否是字母和数字
print(s7.isalpha()) #是否是字母
print(s7.isdigit()) #是否是数字
print(s7.isdecimal()) #是否是数字,包括类似②特殊的数字
print(s7.isnumeric()) #是否是数字,可以判断中文的"二"
s8 = "username\temail\tpassword\ndongfei\tdongfei@qq.com\t123456"
print(s8.expandtabs(20))
s9 = "_123"
print(s9.isidentifier()) #是否是一个标识符,数字、字母、下划线,不能单独数字
s11 = "ja\tck"
print(s11.isprintable())
s12 = " "
print(s12.isspace())
s13 = "this is a title"
s14 = s13.title()
print(s14,s14.istitle()) #This Is A Title True
s15 = "床前明月光"
print("_".join(s15)) #床_前_明_月_光
s16 = " dong fei "
print(s16.lstrip())
print(s16.rstrip())
print(s16.strip())
s17 = "dongfei"
print(s17.lstrip("d"))
s18 = "床前明月光,12345"
s19 = str.maketrans("12345","疑似地上霜")
print(s18.translate(s19)) #床前明月光,疑似地上霜
s20 = "asdftestfdas"
print(s20.partition("s")) #按照”s“做分隔符分割为三份,('a', 's', 'dftestfdas')
print(s20.rpartition("s")) #('asdftestfda', 's', '')
print(s20.split("s")) #['a', 'dfte', 'tfda', '']
print(s20.rsplit("s",2)) #['asdfte', 'tfda', '']
s21 = "qwer\nlllsdf\nsdfggf"
print(s21.splitlines(True)) #['qwer\n', 'lllsdf\n', 'sdfggf'] #保留换行符
print(s21.splitlines(False)) #['qwer', 'lllsdf', 'sdfggf'] #不保留换行符
s24 = "dongfeidongfeidongfei"
print(s24.replace("dong","xi")) #xifeixifeixifei
print(s24.replace("dong","xi",1)) #xifeidongfeidongfei
1. join()
2. split()
3. find()
4. strip()
5. upper()
6. lower()
7. replace()
s22 = "dongfei"
print(s22[0])
print(s22[1])
print(s22[2])
print(s22[3])
print(s22[0:3]) #0 >=; 3 < 结果:don
print(s22[0:-1]) #-1表示最后一个 结果:dongfe
str = ‘0123456789’
print str[0:3] #截取第一位到第三位的字符
print str[:] #截取字符串的全部字符
print str[6:] #截取第七个字符到结尾
print str[:-3] #截取从头开始到倒数第三个字符之前
print str[2] #截取第三个字符
print str[-1] #截取倒数第一个字符
print str[::-1] #创造一个与原字符串顺序相反的字符串
print str[-3:-1] #截取倒数第三位与倒数第一位之前的字符
print str[-3:] #截取倒数第三位到结尾
print str[:-5:-3] #逆序截取
print(len(s22)) #计算字符串占用多少字符
import time
s23 = "飞流直下三千尺,疑似银河落九天。"
index = 0
while index < len(s23):
print(s23[index])
index += 1
time.sleep(1)
import time
s23 = "飞流直下三千尺,疑似银河落九天。"
for i in s23:
print(i)
time.sleep(1)
- 列表中的元素可以被修改
- 列表中的元素可以被删除
- 列表中的元素可以是任何数据类型
- 列表可以嵌套
- 列表是有序的
li = ["dongfei", "M", 18, ["python", "linux"]]
li = ["dongfei", "M", 18, "python", "linux"]
li.append("mysql") #在最后追加一个元素
li.append([123,321])
print(li)
li[0] = "jack"
li[1:2] = ["F", 19]
li = ["dongfei", "M", 18, "python", "linux"]
li2 = li.copy()
print(li)
print(li2)
del li[0]
del li[1:3]
li.clear()
print("dongfei" in li)
print("python" in li[3])
for item in li:
print(item)
print(li[3][0])
a = "abc123"
print(list(a)) #['a', 'b', 'c', '1', '2', '3']
# 第一种方法
li = ["dongfei", "M", 18, "python", "linux"]
s1 = ""
for item in li:
s1 += str(item)
print(type(s1), s1)
# 第二种方法,前提是列表中的元素都是字符串
# s2 = "".join(li)
li = ["dongfei", "M", 18, "python", "linux"]
print(li.count("linux"))
li = [11,22,33,44]
li.extend([55,66])
print(li) #[11, 22, 33, 44, 55, 66]
li = ["dongfei", "M", 18, ["python", "linux"]]
print(li.index("M", 1, 3))
li = ["dongfei", "M", 18, ["python", "linux"]]
li.insert(3, "mysql")
print(li) #['dongfei', 'M', 18, 'mysql', ['python', 'linux']]
li = ["dongfei", "M", 18, ["python", "linux"], "mysql"]
print(li.pop(1)) #M
print(li) #['dongfei', 18, ['python', 'linux'], 'mysql']
li = ["dongfei", "M", 18, ["python", "linux"], "mysql"]
li.remove("dongfei")
print(li) #['M', 18, ['python', 'linux'], 'mysql']
li = ["dongfei", "M", 18, ["python", "linux"], "mysql"]
li.reverse()
print(li) #['mysql', ['python', 'linux'], 18, 'M', 'dongfei']
li = [3, 234 ,5, 556, 3234, 234, 557]
li.sort() #[3, 5, 234, 234, 556, 557, 3234]
# li.sort(reverse=True) #[3234, 557, 556, 234, 234, 5, 3]
print(li)
- 元组的一级元素不可被修改
- 元组不能增加、删除
- 推荐最后加个","
- 可迭代对象
- 有序的
tu = (123, "dongfei", (22, "abc"), ["mysql", "python"], "linux",)
print(tu[1]) #dongfei
print(tu[2:4]) #((22, 'abc'), ['mysql', 'python'])
tu = (123, "dongfei", (22, "abc"), ["mysql", "python"], "linux",)
li = list(tu)
print(li, type(li))
tu = (123, "dongfei", (22, "abc"), ["mysql", "python"], "linux",)
print(tu.count("dongfei")) #1
print(tu.index("dongfei")) #1
- 列表不能作为字典的key,但是元组可以作为字典的key
- 可以做hash的数据类型就可以作为字典的key
- key重复时保留最后一个
- 布尔值也可以作key
info = {
"name": "dongfei",
"age": 18,
"skill": ["python", "linux", "mysql"]
}
print(info)
print(info["name"]) #dongfei
print(info["skill"][0]) #python
info = {
"name": "dongfei",
"age": 18,
"skill": ["python", "linux", "mysql"]
}
del info["age"] #{'name': 'dongfei', 'skill': ['python', 'linux', 'mysql']}
del info["skill"][2] #{'skill': ['python', 'linux'], 'name': 'dongfei', 'age': 18}
print(info)
info = {
"name": "dongfei",
"age": 18,
"skill": ["python", "linux", "mysql"]
}
for item in info: #默认循环所有的key
print(item)
for item in info.keys(): #循环所有key
print(item)
for item in info.values(): #循环所有value
print(item)
for k,v in info.items(): #循环取所有key和value
print(k, v)
copy() 浅拷贝
dict.fromkeys() 将可迭代对象生成字典,key为可迭代对象的元素
print(dict.fromkeys(["k1", 321, "abc"])) #{321: None, 'k1': None, 'abc': None}
info = {
"name": "dongfei",
"age": 18,
"skill": ["python", "linux", "mysql"]
}
print(info.get("name")) #dongfei
print(info.get("nono", "key不存在")) #key不存在
info = {
"name": "dongfei",
"age": 18,
"skill": ["python", "linux", "mysql"]
}
v1 = info.pop("skill")
print(v1) #['python', 'linux', 'mysql']
v2 = info.pop("nono", "key不存在")
print(v2) #key不存在
print(info) #{'age': 18, 'name': 'dongfei'}
info = {
"name": "dongfei",
"age": 18,
"skill": ["python", "linux", "mysql"]
}
print(info.setdefault("name", "maria")) #dongfei
print(info.setdefault("new_name", "jack")) #jack
print(info) #{'age': 18, 'skill': ['python', 'linux', 'mysql'], 'new_name': 'jack', 'name': 'dongfei'}
info = {
"name": "dongfei",
"age": 18,
"skill": ["python", "linux", "mysql"]
}
info.update({"name": "jack", "age":21}) #{'name': 'jack', 'skill': ['python', 'linux', 'mysql'], 'age': 21}
info.update(name="jack", age=21)
print(info)
for item in range(0,10): #1 ~ 9
print(item)
for item in range(0,10,2): #0,2,4,6,8
print(item)
taohuaxi = "一座高桥隔着云烟出现,在岩石的西畔询问渔船。桃花整天随着流水流淌,桃源洞口在清溪的哪边?"
for item in range(len(taohuaxi)):
print(item,taohuaxi[item])
int
replace
find
join
strip
startswith
endswith
split
upper
lower
format
append
extend
insert
get
update
keys
values
items
原文:https://www.cnblogs.com/L-dongf/p/10575194.html