bool isShorter(const string &s1, const string &s2)
{
    return s1.size()<s2.size();
}

int main()
{
    //按长度由短至长排序words
    sort(words.begin(), words.end(), isShorter);
}

近期老碰到排序。冒泡排序什么的已经非常熟悉啦，选择排序不太清楚，什么二分啦，快排啦，哈希啦。就仅仅是知道思路，得努力啊！

！

！

    vector<string> words={"fox","jumps","over","quick","red","red","slow","the","the","turtle"};
    //按长度由短至长排序words
    sort(words.begin(), words.end(), isShorter);
    elimDups(words);    //将words按字典序重排，并消除反复单词
    //按长度重排。长度一样按字典
    stable_sort(words.begin(), words.end(), isShorter);

    for(const auto &s : words)  //无需拷贝字符串
        cout<<s<<" ";   //打印每一个元素
    cout<<endl;

//调用算法进行排序打印长度大于5的元素
    auto it=partition(words.begin(), words.end(), isLong);
    //返回的是使谓词为true的最后一个迭代器
    cout<<"输出长度大于等于5的字符！
！
"<<endl;
    for(vector<string>::iterator st=words.begin() ; st != it ; ++st)
        cout<<*st<<" ";
    cout<<endl;

！！

！

又来了好东西了。大家是不是感觉幸福来的太突然！！！

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！

//是不是有点不一样。这里定义了可调用对象f，它不接受參数。返回42
auto f=[] {return 42;};

    //看哥调用它
    cout<<f()<<endl;

stable_sort(words.begin(), words.end(), [] (const string &a, const string &b)
{return a.size()<b.size();})

void fcn1()
{
    vector<string> words={"fox","jumps","over","quick","red","red","slow","the","the","turtle"};
    size_t v1 = 42;
    //获取一个迭代器，指向第一个满足size()>=v1的元素
    auto wc=find_if(words.begin(), words.end(), [v1](const string &a){return a.size()>=v1;});

}

void fcn2()
{
    vector<string> words={"fox","jumps","over","quick","red","red","slow","the","the","turtle"};
    size_t v1 = 42;
    //获取一个迭代器。指向第一个满足size()>=v1的元素
    auto wc=find_if(words.begin(), words.end(), [v1](const string &a){return a.size()>=v1;});
    //计算满足size>=sz的元素的数目
    auto count=words.end()-wc;
    
    cout<<count<<" "<<make_plural(count, "word", "s")
        <<" of length "<<v1<<" or longer "<<endl;
        
    //for_each算法
    for_each(wc, words.end(),[](const string &s){cout<<s<<" yeah! ";});
}