给定一个非负整数 numRows,生成杨辉三角的前 numRows 行。
在杨辉三角中,每个数是它左上方和右上方的数的和。
示例:
输入: 5 输出: [ [1], [1,1], [1,2,1], [1,3,3,1], [1,4,6,4,1] ]
class Solution { public List<List<Integer>> generate(int numRows) { List<List<Integer>> triangle = new ArrayList<List<Integer>>(); // First base case; if user requests zero rows, they get zero rows. if (numRows == 0) { return triangle; } // Second base case; first row is always [1]. triangle.add(new ArrayList<>()); triangle.get(0).add(1); for (int rowNum = 1; rowNum < numRows; rowNum++) { List<Integer> row = new ArrayList<>(); List<Integer> prevRow = triangle.get(rowNum-1); // The first row element is always 1. row.add(1); // Each triangle element (other than the first and last of each row) // is equal to the sum of the elements above-and-to-the-left and // above-and-to-the-right. for (int j = 1; j < rowNum; j++) { row.add(prevRow.get(j-1) + prevRow.get(j)); } // The last row element is always 1. row.add(1); triangle.add(row); } return triangle; } }
原文:https://www.cnblogs.com/JAYPARK/p/10585815.html