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汇总各个部门当前员工的title类型的分配数目,结果给出部门编号dept_no、dept_name、其当前员工所有的title以及该类型title对应的数目count

时间:2019-04-02 19:50:37      阅读:125      评论:0      收藏:0      [点我收藏+]
CREATE TABLE `departments` (
`dept_no` char(4) NOT NULL,
`dept_name` varchar(40) NOT NULL,
PRIMARY KEY (`dept_no`));
CREATE TABLE `dept_emp` (
`emp_no` int(11) NOT NULL,
`dept_no` char(4) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE IF NOT EXISTS `titles` (
`emp_no` int(11) NOT NULL,
`title` varchar(50) NOT NULL,
`from_date` date NOT NULL,
`to_date` date DEFAULT NULL);

输入描述:

输出描述:

dept_nodept_nametitlecount
d001 Marketing Senior Engineer 1
d001 Marketing Staff 1
d002 Finance Senior Engineer 1
d003 Human Resources Senior Staff 1
d004 Production Senior Engineer 2
d005 Development Senior Staff 1
d006 Quality Management Engineer 2
d006 Quality Management Senior Engineer 1
思路:看创建的表以及结果:tiltle是惟一的,需要的是 departments表和title表里面的dept_no,dept_name和title以及title的重复计数,但是departments和title表没有直接关系,
1.连接dept_emp和titles表,判断to_data=‘9999-01-01’ ,d.emp_no=t.emp_no
2.连接department和1操作之后的表,条件dept_no==
3.group by dept_no,title
SELECT de.dept_no, dp.dept_name, t.title, COUNT(t.title) AS count
FROM titles AS t INNER JOIN dept_emp AS de 
ON t.emp_no = de.emp_no AND de.to_date = 9999-01-01 AND t.to_date = 9999-01-01
INNER JOIN departments AS dp 
ON de.dept_no = dp.dept_no
GROUP BY de.dept_no, t.title

 

汇总各个部门当前员工的title类型的分配数目,结果给出部门编号dept_no、dept_name、其当前员工所有的title以及该类型title对应的数目count

原文:https://www.cnblogs.com/pipiyan/p/10644819.html

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