首页 > 编程语言 > 详细

[LeetCode] Score After Flipping Matrix 翻转数组后的分数

时间:2019-04-09 01:14:43      阅读:170      评论:0      收藏:0      [点我收藏+]



We have a two dimensional matrix?A?where each value is?0?or?1.

A move consists of choosing any row or column, and toggling each value in that row or column: changing all?0s to?1s, and all?1s to?0s.

After making any number of moves, every row of this matrix is interpreted as a binary number, and the score of the matrix is the sum of these numbers.

Return the highest possible?score.

Example 1:

Input: [[0,0,1,1],[1,0,1,0],[1,1,0,0]]
Output: 39
Explanation: Toggled to [[1,1,1,1],[1,0,0,1],[1,1,1,1]].
0b1111 + 0b1001 + 0b1111 = 15 + 9 + 15 = 39

Note:

  1. 1 <= A.length <= 20
  2. 1 <= A[0].length <= 20
  3. A[i][j]?is?0?or?1.



参考资料:

https://leetcode.com/problems/score-after-flipping-matrix/



LeetCode All in One 题目讲解汇总(持续更新中...)

[LeetCode] Score After Flipping Matrix 翻转数组后的分数

原文:https://www.cnblogs.com/grandyang/p/10674440.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!