LeetCode 70 _ Maximum Subarray 最大子数组 (Easy)

Description:

You are climbing a stair case. It takes n steps to reach to the top.

Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?

Note: Given n will be a positive integer.

Example 1:

Input: 2
Output: 2
Explanation: There are two ways to climb to the top.
1. 1 step + 1 step
2. 2 steps

Example 2:

Input: 3
Output: 3
Explanation: There are three ways to climb to the top.
1. 1 step + 1 step + 1 step
2. 1 step + 2 steps
3. 2 steps + 1 step

Solution:

Code:

public int climbStairs(int n) {
    if (n <= 1){
        return 1;
    }
    int[] res = new int[n];
    res[0] = 1; res[1] = 2;
    for (int i = 2; i < n; i++){
        res[i] = res[i-1] + res[i-2];
    }
    return res[n-1];
}

提交情况:

Runtime: 0 ms, faster than 100.00% of Java online submissions for Climbing Stairs.
Memory Usage: 31.9 MB, less than 100.00% of Java online submissions for Climbing Stairs.

LeetCode 70 _ Maximum Subarray 最大子数组 (Easy)

原文：https://www.cnblogs.com/zingg7/p/10679070.html