class Solution {
public:
vector<int> multiply(const vector<int>& A) {
vector<int> res;
int n = A.size();
res.push_back(1);
//res中存每个累积的乘积
for(int i = 1; i < n; i++){
res.push_back(res.back() *A[i-1]);
}
//tmp累积从后往前的乘积
int tmp = 1;
for(int i = res.size()-1; i >= 0; i--){
res[i] = res[i]*tmp;
tmp *= A[i];
}
return res;
}
};
原文:https://www.cnblogs.com/chengsheng/p/10692904.html