awk进阶

1.[4@izuf60jasqavbxb9efockpz ~]$ echo $PATH | awk ‘BEGIN{FS=":"}‘‘{print $0}‘

/usr/local/bin:/usr/bin:/usr/local/sbin:/usr/sbin:/home/4/.local/bin:/home/4/bin:/home/16116374/test

[4@izuf60jasqavbxb9efockpz ~]$ echo $PATH | awk ‘BEGIN{RS=":"}‘‘{print $0}‘

/usr/local/bin
/usr/bin
/usr/local/sbin
/usr/sbin
/home/4/.local/bin
/home/4/bin
/home/4/test

RS会根据制定的分隔符换行

2.[4@izuf60jasqavbxb9efockpz ~]$ echo $PATH | awk ‘BEGIN{FS=":"}‘‘{print $0}‘

/usr/local/bin:/usr/bin:/usr/local/sbin:/usr/sbin:/home/4/.local/bin:/home/4/bin:/home/4/test

3.[4@izuf60jasqavbxb9efockpz ~]$echo $PATH | awk ‘BEGIN{FS=":"}‘‘{print $1}‘

/usr/local/bin

科学计算与词典使用

4.awk ‘BEGIN{print 3*7}‘

21

5.echo | awk ‘{print 3*7}‘

21

6.awk ‘BEGIN{printf "%.3f\n",3/7}‘

0.429

7.awk ‘BEGIN{printf "%.f\n",3/7}‘

0

8.awk ‘BEGIN{printf "%.1f\n",3/7}‘

0.4

9.seq 10 2 20

10
12
14
16
18
20

步数为2

10.seq 10 2 20 | awk ‘{sum+=$1}{print sum}‘

10
22
36
52
70
90

11.seq 10 2 20 | awk ‘{sum+=$1}{print sum,NR}‘

10 1
22 2
36 3
52 4
70 5
90 6

12.seq 10 2 20 | awk ‘{sum+=$1}{print sum/NR}‘

10
11
12
13
14
15

13.seq 10 20 | awk ‘$1>19‘

20

大于19

14. seq 10 2 20 | awk ‘$1>14 {data[NR]=$1}{for (k in data) print data[k]}‘

16
16
18
16
18
20

15.seq 10 2 20 | awk ‘$1>14 {data[NR]=$1}END{for (k in data) print data[k]}‘

16
18
20

awk进阶

原文：https://www.cnblogs.com/godlove/p/10697900.html