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java多线程(4)模拟排队叫号程序,不能出现交替执行的结果

时间:2019-04-19 19:21:07      阅读:211      评论:0      收藏:0      [点我收藏+]

package com.javaconcurrencyprogramming.chapter1;

/**
* @description: 模拟有错误的排队叫号程序
* @author:
* @create:
**/

public class TicketWindow extends Thread{

//柜台名称
private final String name;

//最多受理50笔业务
private static final int MAX = 500;

// private int index = 1;
private static int index = 1;

public TicketWindow(String name){
this.name = name;
}

@Override
public void run(){
while (index <= MAX){

System.out.println("柜台:" + name + " 当前的号码是:" + (index++));
}
}

public static void main(String[] args) {
TicketWindow ticketWindow1 = new TicketWindow("一号出号机");
ticketWindow1.start();

TicketWindow ticketWindow2 = new TicketWindow("一号出号机");
ticketWindow2.start();

TicketWindow ticketWindow3 = new TicketWindow("一号出号机");
ticketWindow3.start();

TicketWindow ticketWindow4 = new TicketWindow("一号出号机");
ticketWindow4.start();
}

}

java多线程(4)模拟排队叫号程序,不能出现交替执行的结果

原文:https://www.cnblogs.com/herosoft/p/10737685.html

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