位操作运算
置位/复位
- 要求:置位int/char等数据中第pos位为0或1
- 原理:
1 & 1 = 1
0 & 1 = 0
1 | 1 = 1
0 | 1 = 1
-> A & 1 = A; A | 1= 1;
0 & 0 = 0;
1 & 0 = 0;
0 | 0 = 0;
1 | 0 = 1;
-> A & 0 = 0; A | 0 = A;
- 结论
置1: 按位或1;
置0: 按位与0;
保持不变:与1/或0
- 示例:
置8bit数据data第3位(0~7):
置1:data | 00001000
置0:data & 11110111
00001000 = (0x01<<3)
11110111 = ~(0x01<<3)
位操作运算
原文:https://www.cnblogs.com/Vannci/p/10756940.html