# 1、使用while循环输出 1 2 3 4 5 6 8 9 10 count = 0 while count < 10: count += 1 if count == 7: continue print(count)
# 2、输出 1-100 内的所有奇数 count = 0 while count < 100: count += 1 if count % 2 == 1: print(count)
# 3、求1-2+3-4+5 ... 99的所有数的和 sum_i = 0 for i in range(0, 100): if i % 2 == 1: sum_i += i else: sum_i -= i print(sum_i)
# 4、计算 1 - 2 + 3 ... + 99 中除了88以外所有数的总和 count = 0 sum_count = 0 while count < 99: count += 1 if count == 88: continue if count % 2 == 0: sum_count -= count else: sum_count += count print(sum_count)
# 5、计算 1 - 2 + 3 ... -99 中除了88意外所有数的总和 i = 0 j = -1 sum_i = 0 while i < 99: i += 1 if i == 88: continue else: j = -j sum_i += i*j print(sum_i)
原文:https://www.cnblogs.com/wt7018/p/10800361.html