a + b
Time Limit: 2000/1000MS (Java/Others)Memory Limit: 128000/64000KB (Java/Others)Problem Description
Input
Output
Sample Input
2 3 1 1 2 3 3 10 1 2 3
Sample Output
6 60074
/*************************************************************************
> File Name: 1007.cpp
> Author: Stomach_ache
> Mail: sudaweitong@gmail.com
> Created Time: 2014年08月11日 星期一 07时44分39秒
> Propose:
************************************************************************/
#include <cstdio>
/*Let‘s fight!!!*/
typedef long long LL;
const LL mod = (LL)1e10 + 7;
LL mul(LL a, LL b) {
LL res = 0;
while (b) {
if (b&1) if ((res += a) >= mod) res -= mod;
a <<= 1;
if (a >= mod) a -= mod;
b >>= 1;
}
return res;
}
LL mod_pow(LL a, LL b) {
LL res = 1;
while (b) {
if (b&1) res = mul(res, a);
a = mul(a, a);
b >>= 1;
}
return res;
}
int main(void) {
int t;
scanf("%d", &t);
while (t--) {
LL n, k, ans = 0, x;
scanf("%lld %lld", &n, &k);
k %= 9560995488LL;
for (int i = 0; i < n; i++) {
scanf("%lld", &x);
ans += mod_pow((x%mod+mod)%mod, k);
if (ans >= mod) ans -= mod;
}
printf("%lld\n", ans);
}
return 0;
}
ACdream 1007 (快速幂),布布扣,bubuko.com
原文:http://www.cnblogs.com/Stomach-ache/p/3904074.html