线段树 I - Transformation

I - Transformation

InputThere are no more than 10 test cases. 
For each case, the first line contains two numbers n and m, meaning that there are n integers and m operations. 1 <= n, m <= 100,000. 
Each the following m lines contains an operation. Operation 1 to 3 is in this format: "1 x y c" or "2 x y c" or "3 x y c". Operation 4 is in this format: "4 x y p". (1 <= x <= y <= n, 1 <= c <= 10,000, 1 <= p <= 3) 
The input ends with 0 0. 
OutputFor each operation 4, output a single integer in one line representing the result. The answer may be quite large. You just need to calculate the remainder of the answer when divided by 10007.Sample Input

5 5
3 3 5 7
1 2 4 4
4 1 5 2
2 2 5 8
4 3 5 3
0 0

Sample Output

307
7489



题目思路：
这个题目是一个裸的线段树，有四种操作，
第一种就是区间更新，在每一个数值+c
第二种就是每一个位置*c
第三种就是把每一个位置的数更新成c
第四种求每一个数的c次方的和
前面三种就是普通的线段树，最后一种因为c比较小，最大只有三所以就在结构体里面枚举三种情况就可以了。
第一种和第二张要设置两个lazy标志，第三种也要设置，但是如果第三种成立则之前的lazy标志都要删去，一共有了三种lazy标志。

线段树 I - Transformation

原文：https://www.cnblogs.com/EchoZQN/p/10853562.html