首页 > 编程语言 > 详细

C++中Lambda表达式转化为函数指针

时间:2019-05-18 20:50:15      阅读:513      评论:0      收藏:0      [点我收藏+]


// -----------------------------------------------------------

auto combineCallbackLambda = [](GLdouble coords[3], void* vertex_data[4], GLfloat weight[4], void** dataOut) mutable -> void CALLBACK
{
  GLdouble * *vertex_data1 = (GLdouble * *)vertex_data;
  GLdouble* vertex = new GLdouble[7];
  vertex[0] = coords[0];
  vertex[1] = coords[1];
  vertex[2] = coords[2];
  for (int i = 3; i < 7; i++)
    vertex[i] = weight[0] * vertex_data1[0][i] + weight[1] * vertex_data1[1][i] + weight[2] * vertex_data1[2][i] + weight[3] * vertex_data1[3][i];
  *dataOut = vertex;
};

void (*combineCallbackFunction)(GLdouble coords[3], void* vertex_data[4], GLfloat weight[4], void** dataOut) = combineCallbackLambda;


// ----------------------------但[]中含有捕获时不能转换-------------------------------


auto vertexCallbackLambda = [&genPositionList, &genTriangle, &genPointIndex](void* vertex_data) mutable -> void CALLBACK
{
  fprintf(stdout, "Tessellation vertexCallback");
  GLdouble* pt = (GLdouble*)vertex_data;
  genTriangle[genPointIndex++] = pt;
  if (genPointIndex >= 3)
  {
    genPositionList.push_back(genTriangle[0]);
    genPositionList.push_back(genTriangle[1]);
    genPositionList.push_back(genTriangle[2]);
    genPointIndex = 0;
  }
};

//void (*vertexCallbackFunction)(void*) = vertexCallbackLambda;

C++中Lambda表达式转化为函数指针

原文:https://www.cnblogs.com/gispathfinder/p/10886994.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!