leetcode1046

 1 import heapq
 2 class Solution:
 3     def lastStoneWeight(self, stones: ‘List[int]‘) -> int:
 4         heapq._heapify_max(stones)
 5         #r = [heapq._heappop_max(stones) for _ in range(len(stones))]
 6         
 7         while len(stones) >= 2:
 8             top = heapq._heappop_max(stones)
 9             top2 = heapq._heappop_max(stones)
10             left = abs(top-top2)
11             if left != 0:
12                 heapq.heappush(stones, left)
13                 heapq._heapify_max(stones)
14         if len(stones) == 1:
15             last = heapq._heappop_max(stones)
16             return last
17         else:
18             return 0