目的是从服务器端下载一个图片从而实现文件传输
1 protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { 2 //1.1获取文件名 3 String filename = request.getParameter("filename"); 4 5 //1.2获得文件路径 6 ServletContext servletContext = this.getServletContext(); 7 String realPath = servletContext.getRealPath("/img/" + filename); 8 9 System.out.println(realPath); 10 //1.3将文件读入内存中:输入流 11 FileInputStream fis = new FileInputStream(realPath); 12 13 //2.1设置response 的响应头类型 14 String mimeType = servletContext.getMimeType("filename"); 15 response.setHeader("content-type","mimeType"); 16 //2.2设置response的响应头的打开方式 17 response.setHeader("content-disposition","attachment;filename="+filename); 18 19 //3.将文件输出:输出流 20 ServletOutputStream sos = response.getOutputStream(); 21 byte[] buff = new byte[1024 * 5]; 22 int len = 0; 23 while((len = fis.read(buff)) != -1){ 24 sos.write(buff, 0, len); 25 } 26 fis.close();
原文:https://www.cnblogs.com/zbzb1/p/10898588.html