简单电商购物程序

def like():
    i = 1  # 为了通过修改i 退出多重循环
    allChoice = []
    while (i):
        for num in range(len(shop)):  # 打印商品列表
            print(str(shop[num][0]).ljust(5), shop[num][1].ljust(20), str(shop[num][2]).ljust(10),
                  str(shop[num][3]).ljust(10))
        choice = input("请输入要加入购物车的商品编号：")
        choice = [int(it) for it in choice.split(‘ ‘)]
        allChoice += choice  # choice是单次选择的商品列表，allchoice是所有选择的商品列表
        while (1):
            total = 0
            choiceSet = set(allChoice)  # 转换成集合，便于不重复计数
            for it in choiceSet:
                print(shop[it - 1][0], shop[it - 1][1], shop[it - 1][2], ‘*‘, allChoice.count(it))
                total += shop[it - 1][2] * allChoice.count(it)
            print("总计：", total, )
            print("---------------------------------\n"
                  "1：继续选购 2:整理购物车 Buy：结算\n")
            option = input("请选择：")
            if option == ‘1‘:
                break
            elif option == ‘2‘:
                item_num = int(input("请输入要删除的商品："))
                allChoice.remove(item_num)  # 每次只会删除一个元素
                continue
            if option == ‘Buy‘:
                for it in choiceSet:
                    print(shop[it - 1][0], shop[it - 1][1], shop[it - 1][2], ‘*‘, allChoice.count(it))
                    total += shop[it - 1][2] * allChoice.count(it)
                print("总计：", total, )
                i = 0
                break
            else:
               print("输入错误请重新输入！")



a=input("请输入“汽车”或“食物”：")
if a=="汽车":
    shop = [[‘1‘, ‘奔驰‘, 150000, ‘汽车‘], [‘2‘, ‘宝马‘, 100000, ‘汽车‘], [‘3‘, ‘越野‘, 28000, ‘汽车‘],
            [‘4‘, ‘沃尔沃‘, 12000, ‘汽车‘],
            [‘5‘, ‘野马‘, 450000, ‘汽车‘], [‘6‘, ‘奥迪‘, 230000, ‘汽车‘], [‘7‘, ‘红旗‘, 100000, ‘汽车‘]]
    like()
elif a=="食物":
    shop = [[‘1‘, ‘苹果‘, 15, ‘水果‘], [‘2‘, ‘葡萄‘, 12, ‘水果‘], [‘3‘, ‘水蜜桃‘, 14, ‘水果‘],
            [‘4‘, ‘香蕉‘, 3, ‘水果‘],
            [‘5‘, ‘梨‘, 1, ‘水果‘],]
    like()