使用xpath解析指定节点数据，适用多层子节点遍历
1.依赖的jar包
<dependency>
<groupId>jaxen</groupId>
<artifactId>jaxen</artifactId>
<version>1.1.6</version>
</dependency>
<dependency>
<groupId>dom4j</groupId>
<artifactId>dom4j</artifactId>
<version>1.6.1</version>
</dependency>
2.示例xml
<?xml version="1.0" encoding="UTF-8"?>
<Doc>
<a>
<a1>a1</a1>
<a2>a2</a2>
<a3>
<a31>龙妈</a31>
<a32>卓跟</a32>
</a3>
<a3>
<a31>穷</a31>
<a32>小白</a32>
</a3>
</a>
<a>
<a1>a11</a1>
<a2>a21</a2>
<a3>
<a31>龙妈和穷</a31>
<a32>三龙齐飞</a32>
</a3>
<a3>
<a31>铁王座</a31>
<a32>穷</a32>
</a3>
</a>
</Doc>
3.读取xml
SAXReader reader = new SAXReader(); Document doc = reader.read("D:\\1.xml"); //获取xml中节点名为a的所有节点，不能为根节点 List<Element> aList = doc.selectNodes("//a"); for (int i=0;i<aList.size();i++){ Element a = aList.get(i); //selectSingleNode只适用于1:1 //只会存在一个节点，如存在多个节点使用selectNodes Element a1 = (Element)a.selectSingleNode("a1"); Element a2 = (Element)a.selectSingleNode("a2");
//此处根据实际xml数据判断a1,a2节点是否=null，如果是必有节点，无需判断
//if(a1==null) continue;
//根据业务逻辑取对应节点数据，只筛选a1=a11的数据 if (!"a11".equals(a1.getTextTrim())) { continue; } System.out.println("a2= "+a2.getTextTrim()); //多个子节点，使用此方法， List<Element> a3List = a.selectNodes("a3"); for (int j=0;j<a3List.size();j++){ Element a3 = a3List.get(j); Element a31 = (Element) a3.selectSingleNode("a31"); Element a32 = (Element) a3.selectSingleNode("a32"); System.out.println("a31= "+a31.getTextTrim()); System.out.println("a32= "+a32.getTextTrim()); } }
打印如下：
a2= a21 a31= 龙妈和穷 a32= 三龙齐飞 a31= 铁王座 a32= 穷
原文：https://www.cnblogs.com/yln20170705/p/10906078.html