思路:贪心策略,对每个区间进行排序,然后先总的全区间为(0,0),然后,对区间不断的更新操作。每次只要去相对上的最大区间即可。
#include<iostream> #include<cmath> #include<algorithm> using namespace std; const int maxn = 10010; double l, w; pair<double, double>a[maxn]; int n; int main(){ while (cin >> n >> l >> w){ int m = 0; for (int i = 0; i < n; ++i) { double x, r; cin >> x >> r; if (w>2 * r)continue; double temp = sqrt(r*r - w*w / 4); a[m++] = make_pair(x - temp, x + temp); //计算区间 } sort(a, a + m); double low = 0, up = 0; int cnt = 0; bool flag = 0; for (int i = 0; i < m; ++i) { if (a[i].first>up){ break; } //保证新的区间与总的区间有交集 if (a[i].second > up){ for (int j = i; j < m&&a[j].first <= low;++j) if (a[j].second>up){ up = a[j].second; //更新总的区间 } cnt++; if (up >= l){ flag = 1; break; } low = up; } } cout << (flag ? cnt : -1) << endl; } }
贪心,区间覆盖问题 Watering Grass UVA - 10382
原文:https://www.cnblogs.com/ALINGMAOMAO/p/10909023.html