Implement wildcard pattern matching with support for?‘?‘
?and?‘*‘
.
‘?‘ Matches any single character. ‘*‘ Matches any sequence of characters (including the empty sequence). The matching should cover the entire input string (not partial). The function prototype should be: bool isMatch(const char *s, const char *p) Some examples: isMatch("aa","a") → false isMatch("aa","aa") → true isMatch("aaa","aa") → false isMatch("aa", "*") → true isMatch("aa", "a*") → true isMatch("ab", "?*") → true isMatch("aab", "c*a*b") → false
class Solution {
public:
//主要是 * 的匹配。 p 每遇到一个 *, 就保存当前*的坐标和s的坐标。然后s继续往前扫描
//假设不成功,则 s会到之前记录的下一个位置,又一次扫描
bool isMatch(const char *s, const char *p) {
if(s == nullptr || p == nullptr) return true;
if(*p == ‘\0‘) return *s == ‘\0‘;
const char *str(nullptr), *star(nullptr);
while(*s) {
if(*s == *p || *p == ‘?‘) {
++s, ++p;
continue;
}
if(*p == ‘*‘) {
star = p;
str = s;
++p;
continue;
}
if(*s != *p) {
if(str == nullptr) return false;
p = star;
s = ++str;
++p;
}
}
while(*p == ‘*‘) ++p;
return *p == ‘\0‘;
}
};
原文:https://www.cnblogs.com/mqxnongmin/p/10932764.html