Parallel and Perpendicular

int a[2][110];
int main()
{
    int n;
    a[0][4] = 0;
    a[0][5] = 0;
    a[0][6] = 6;
    a[1][4] = 2;
    a[1][5] = 0;
    a[1][6] = 9;
    while (~RI(n))
    {
        if (n <= 6)
        {
            printf("%d %d\n", a[0][n], a[1][n]);
        }
        else
        {
            cout << 1LL * (n - 3) * n / 2 << ' ';
            if (n & 1) cout << 0 << endl;
            else cout << 1LL * (n - 3) * n / 2 << endl;
        }
    }
    return 0;
}